00:01
Okay, so here we have f of x is equal to side of 2x minus x, where we have zero less than equal to x, which is less than or equal to pi.
00:08
So we differentiate here on a given domain, and we get that f prime of x is then going to be equal to two times cosine of 2x and then minus one.
00:22
And then we take our derivative here and set it equal to zero on our domain.
00:28
So we have 2x or 2 times cosine of 2x, which is then going to be equal to 1.
00:35
That implies that cosine of 2, of 2x is then going to be equal to 1 half.
00:44
So in other words, we get that 2x is going to be equal to pi over 3 or 5 pi over 3 gives us that x is equal to pi over 6 or 5 pi over 6.
00:58
So therefore, x here is going to be equal to pi over six or five pi over six.
01:05
Okay, so there we have our two critical points here.
01:10
And then we can differentiate again.
01:13
So we get f double prime of x is then going to be equal to a negative four times sign of 2x.
01:22
And then we look at our critical points.
01:24
So we do f double prime of, um, of pi over six, which is going to give us a negative four times side of two pi over six.
01:37
So that's negative four times sine of two pi over six is square root of three over two.
01:44
So this here is going to be less than zero...