00:01
In this question we have given the demand function 20 -0 .02x.
00:08
Let's say it as equation 1 and we have to find the elasticity of demand at x equal to 560.
00:15
So, first we will simply put x equal to 560 so it will be 20 -0 .02 multiplied by 560.
00:27
On solving it, it will be 8 .8.
00:34
Now, the elasticity of demand is given by p by x multiplied by dx by dp and it will be in the modulus.
00:59
So, as we know p equals to 20 -0 .02x so x will be 20 -p by 0 .02.
01:18
So first we will find the dx by dp.
01:22
So, dx by dp will be differentiation of 20 -p by 0 .02 with respect to p.
01:39
So we can simply see its differentiation as the differentiation of 20 will be 0 as it is constant and the differentiation of minus p will be minus 1.
01:49
So, the result will be minus 1 by 0 .02.
01:54
This is the value of dx by dp...