Question

The density of nickel (Ni) is 8.90 g/mL and the cell volume is 4.38 × 10^(-23) mL. Determine the number of atoms in the unit cell. (Because there cannot be a part of an atom in a unit cell, we must round the number of atoms to the nearest whole number.) atoms

Name: the density of nickel ni is 890 gml and the cell volume is 438 1023 ml determine the number of atoms in the unit cell because there cannot be a part of an atom in a unit cell we must round t 27753
Uploaded: 2022-09-07T17:50:08-08:00
Duration: 1 min 11 s
Channel: John Incabo
Description: the density of nickel ni is 890 gml and the cell volume is 438 1023 ml determine the number of atoms in the unit cell because there cannot be a part of an atom in a unit cell we must round t 27753

          The density of nickel (Ni) is 8.90 g/mL and the cell volume is 4.38 × 10^(-23) mL. Determine the number of atoms in the unit cell. (Because there cannot be a part of an atom in a unit cell, we must round the number of atoms to the nearest whole number.) atoms

Added by Shelly H.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert John Incabo

09/07/2022

Step 1

90 g/mL and cell volume = 4.38 × 10^(-23) mL Mass = density x volume Mass = 8.90 g/mL x 4.38 × 10^(-23) mL Mass = 3.90 x 10^(-22) g ** Show more…

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The density of nickel (Ni) is 8.90 g/mL and the cell volume is 4.38 × 10^(-23) mL. Determine the number of atoms in the unit cell. (Because there cannot be a part of an atom in a unit cell, we must round the number of atoms to the nearest whole number.) atoms