The differential equation below models the temperature of an 89°C cup of coffee in a 21°C room, where t is the time in minutes. It is known that the coffee cools at a rate of 1°C per minute when its temperature is 71°C. Solve the differential equation to find an expression for the temperature of the coffee at time t. (Let Y be the temperature of the coffee when the temperature was 89°C.) $$ \frac{dy}{dt} = -\frac{1}{50}(y - 21) $$
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We can separate the variables y and t: $$ \frac{dy}{y - 21} = -\frac{1}{50} dt $$ Show more…
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The differential equation below models the temperature of an 93°C cup of coffee in a 19°C room, where it is known that the coffee cools at a rate of 1°C per minute when its temperature is 69°C. Solve the differential equation to find an expression for the temperature of the coffee at time t. (Let y be the temperature of the cup of coffee in °C, and let t be the time in minutes, with t = 0 corresponding to the time when the temperature was 93°C.) dy/dt = -1/50(y - 19) y = 19 + 69e^(-t/50)
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Consider a 80° cup of coffee in a 20° room. Suppose it is known that the coffee cools at a rate of 1°C per minute when its temperature is 70°. a) What is the differential equation in this case? dy/dt= ? (b) Sketch a direction field and use it to sketch the solution curve for the initial-value problem. (Do this on paper. Your instructor may ask you to turn in this sketch.) What is the limiting value of the temperature? T=? °C c) Use Euler's method with step size h = 2 minutes to estimate the temperature of the coffee after 10 minutes, y(10). (Round your answer to the nearest hundredth.) y(10)= ? °C
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