00:01
Hello everyone, welcome to this video.
00:03
So here we are given with a vector a b c.
00:06
We have to find b plus c.
00:10
So b plus c is given by 3 plus 7.
00:15
So that will be equal to 10.
00:18
Now we have to find magnitude and direction of the vector b plus c.
00:26
So to find that let us take as magnitude is equal to b plus c.
00:35
So let us take the magnitude as v squared which is given by 3 squared plus 7 squared will be equal to 58.
00:53
So therefore the magnitude is given by root of 58.
00:59
Therefore the magnitude of vector b and c that is v is given by root 58.
01:09
The value is 7 .62.
01:13
Now we have to find the direction.
01:15
So direction we have to find the angle theta.
01:20
So angle theta we have the formula tan inverse of b by a.
01:26
So using this let us find out.
01:29
So here our tan inverse b value is given by 7 .62 and the a value which we have is 3.
01:43
So respective to the vector b and c.
01:45
So here we have tan inverse of 7 .62 by 3.
01:51
So therefore we get the theta value that is the direction is given by theta is equal to 68 .51.
02:01
Now let us find the next one.
02:03
Next we have to find a dot b plus c.
02:07
So already we have b plus c is equal to 7 and a vector is given by 3...