The electrode potential for a calcium ion selective electrode is 0.150 V in 7.5 x 10-6 M Ca(NO3)2. What will the potential be when 0.800 M H+ is added if kca2+,H+ is 1.3 x 10-5? Assume that concentration equals activity.
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Step 1
The Nernst equation is given by: E = E° - (RT/nF) * ln(Q) Where: E = electrode potential E° = standard electrode potential R = gas constant (8.314 J/(mol*K)) T = temperature in Kelvin n = number of electrons transferred in the reaction F = Faraday constant (96485 Show more…
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