The empirical formula for tin oxide is SnO2. 0.7725 g of tin is reacted with excess nitric acid. Assuming all of the tin reacts, how much tin oxide is formed? Answer:
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In an experiment $0.500 \mathrm{~g}$ of tin reacted with nitric acid to give tin oxide. If the oxide had a mass of $0.635 \mathrm{~g}$, what is the empirical formula of tin oxide?
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