The enthalpy of vaporization of ethanol is 38.56 kJ/mol at its boiling point of 78.37°C. Determine the entropy of vaporization of ethanol at this temperature.
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The formula to convert Celsius to Kelvin is K = °C + 273.15. So, the boiling point of ethanol in Kelvin is 78.37 + 273.15 = 351.52 K. The entropy of vaporization (∆Svap) can be calculated using the formula ∆Svap = ∆Hvap / T, where ∆Hvap is the enthalpy of Show more…
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