Question

Find the equation of a plane passing through the point (-1, -4, 3) and perpendicular to the line x = -1 - 2t, y = 5 + t, z = 4 - 2t

Name: Find the equation of a plane passing through the point (-1, -4, 3) and perpendicular to the line x = -1 - 2t, y = 5 + t, z = 4 - 2t
Uploaded: 2023-09-11T18:25:16-08:00
Duration: 1 min 53 s
Channel: Adi S
Description: Find the equation of a plane passing through the point (-1, -4, 3) and perpendicular to the line x = -1 - 2t, y = 5 + t, z = 4 - 2t

          Find the equation of a plane passing through the point (-1, -4, 3) and perpendicular to the line x = -1 - 2t, y = 5 + t, z = 4 - 2t

Added by Joshua K.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

09/11/2023

Step 1

The direction vector of the line is given by the coefficients of t in the parametric equations. So, the direction vector is < -2, 1, -2 >. Show more…

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The equation of a plane passing through the point (-1, -4, 3) and perpendicular to the line x = -1 - 2t, y = 5 + t, z = 4 - 2t is:

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Find the equation of a plane passing through the point (-1, -4, 3) and perpendicular to the line x = -1 - 2t, y = 5 + t, z = 4 - 2t

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