Question

The equation \frac{t^2}{y^2} - \cos(6y) = -2 implicitly defines y as a function of t. Find \frac{dy}{dt}

Name: The equation (t^2)/(y^2) - cos(6y) = -2 implicitly defines y as a function of t. Find (dy)/(dt)
Uploaded: 2023-03-23T12:23:34-08:00
Duration: 2 min 6 s
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Description: The equation (t^2)/(y^2) - cos(6y) = -2 implicitly defines y as a function of t. Find (dy)/(dt)

          The equation \frac{t^2}{y^2} - \cos(6y) = -2 implicitly defines y as a function of t. Find \frac{dy}{dt}

Added by Andrea M.

Calculus: Early Transcendentals

James Stewart 8th Edition

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The equation -(t^(2))/(y^(2))-cos(6y)=-2 implicitly defines y as a function of t. Find (dy)/(dt). (dy)/(dt)= The equation 2 cos (6 y) = 2 implicitly defines y as a function of dy Find at ain(a) A dy dt