Question

4. The exact value of $\sin\left(-\frac{\pi}{6}\right) + \cos\left(\frac{7\pi}{4}\right)$ is: $\frac{\sqrt{2}+1}{2}$ $\frac{\sqrt{3}-\sqrt{2}}{2}$ $\frac{\sqrt{3}+\sqrt{2}}{2}$ $\frac{\sqrt{2}-1}{2}$

          4. The exact value of $\sin\left(-\frac{\pi}{6}\right) + \cos\left(\frac{7\pi}{4}\right)$ is:
$\frac{\sqrt{2}+1}{2}$
$\frac{\sqrt{3}-\sqrt{2}}{2}$
$\frac{\sqrt{3}+\sqrt{2}}{2}$
$\frac{\sqrt{2}-1}{2}$

4. The exact value of sin(-(π)/(6)) + cos((7π)/(4)) is:
(√(2)+1)/(2)
(√(3)-√(2))/(2)
(√(3)+√(2))/(2)
(√(2)-1)/(2)

Added by Thomas C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Suman Saurav Thakur

07/07/2020

Step 1

Step 1: We know that sin(-π/6) = -1/2 and cos(7π/4) = 1/√2. Show more…

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The exact value of sin(-(pi )/(6))+cos((7pi )/(4)) is: (sqrt(2)+1)/(2) (sqrt(3)-sqrt(2))/(2) (sqrt(3)+sqrt(2))/(2) (sqrt(2)-1)/(2) 4 Prev Next 481 The exact value of sin + V2 +1 2 V3-V2 2 V3+V2 2 V2 1 2 Prev Next