Question

The figure below shows a charged particle, with a charge of q = +41.0 nC, that moves a distance of d = 0.181 m from point A to point B in the presence of a uniform electric field E of magnitude 290 N/C, pointing right. A positive point charge q is initially at point A, then moves a distance d to the right to point B. The electric field vector E points to the right. (a) What is the magnitude (in N) and direction of the electric force on the particle? Magnitude: N Direction: toward the right (b) What is the work (in J) done on the particle by the electric force as it moves from A to B? Work: J (c) What is the change of the electric potential energy (in J) as the particle moves from A to B? (The system consists of the particle and all its surroundings.) PEB - PEA = J (d) What is the potential difference (in V) between A and B? VB - VA = V

          The figure below shows a charged particle, with a charge of q = +41.0 nC, that moves a distance of d = 0.181 m from point A to point B in the presence of a uniform electric field E of magnitude 290 N/C, pointing right. A positive point charge q is initially at point A, then moves a distance d to the right to point B. The electric field vector E points to the right.

(a) What is the magnitude (in N) and direction of the electric force on the particle?
Magnitude: N
Direction: toward the right

(b) What is the work (in J) done on the particle by the electric force as it moves from A to B?
Work: J

(c) What is the change of the electric potential energy (in J) as the particle moves from A to B? (The system consists of the particle and all its surroundings.)
PEB - PEA = J

(d) What is the potential difference (in V) between A and B?
VB - VA = V

Added by Shelley M.

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