The figure below shows a dipole. If the positive particle has a charge of 32.5 mC and the particles are 2.44 mm apart, what is the electric field at point ( A ) located 2.00 mm above the dipole's midpoint? (Express your answer in vector form.) [ overrightarrow{oldsymbol{E}}=square mathrm{N} / mathrm{C} ]
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The positive charge \( q = 32.5 \, \text{mC} = 32.5 \times 10^{-3} \, \text{C} \) and the negative charge \( -q \) are separated by a distance \( d = 2.44 \, \text{mm} = 2.44 \times 10^{-3} \, \text{m} \). Show more…
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