Question

The figure below shows two blocks connected by a string of negligible mass passing over a frictionless pulley. $m_1 = 3.8$ kg and $\theta = 12.0^\circ$. Assume that the incline is smooth. (a) For what value of $m_2$ (in kg) will the system be in equilibrium? $m_2 = 0.79$ Did you draw two free-body diagrams, one for each mass and identify the forces acting on each of them? For $m_2$ take the $+x$-axis to be down the incline and the $y$-axis to be perpendicular to the incline. kg (b) If the block has to slide down the incline with an acceleration of 0.6 m/s$^2$, what should be the value of $m_2$ (in kg)? $m_2 = 0.557$ Check for consistency in the sign of each force. kg

          The figure below shows two blocks connected by a string of negligible mass passing over a frictionless pulley. $m_1 = 3.8$ kg and $\theta = 12.0^\circ$. Assume that the incline is smooth.

(a) For what value of $m_2$ (in kg) will the system be in equilibrium?
$m_2 = 0.79$

Did you draw two free-body diagrams, one for each mass and identify the forces acting on each of them? For $m_2$ take the $+x$-axis to be down the incline and the $y$-axis to be perpendicular to the incline. kg

(b) If the block has to slide down the incline with an acceleration of 0.6 m/s$^2$, what should be the value of $m_2$ (in kg)?
$m_2 = 0.557$

Check for consistency in the sign of each force. kg

The figure below shows two blocks connected by a string of negligible mass passing over a frictionless pulley. m1 = 3.8 kg and θ = 12.0^∘. Assume that the incline is smooth.

(a) For what value of m2 (in kg) will the system be in equilibrium?
m2 = 0.79

Did you draw two free-body diagrams, one for each mass and identify the forces acting on each of them? For m2 take the +x-axis to be down the incline and the y-axis to be perpendicular to the incline. kg

(b) If the block has to slide down the incline with an acceleration of 0.6 m/s^2, what should be the value of m2 (in kg)?
m2 = 0.557

Check for consistency in the sign of each force. kg

Added by Kevin D.

Question

Please give Ace some feedback