Question

The figure shows a particle that carries a charge of q0 = -2.85 × 10^-6 C. It is moving along the +y axis at a speed of v = 4.99 × 10^6 m/s. A magnetic field B of magnitude 3.45 × 10^-5 T is directed along the +z axis, and an electric field E of magnitude 112 N/C points along the -x axis. Determine (a) the magnitude and (b) direction (as an angle within x-y plane with respect to +x-axis in the range (-180°, 180°]) of the net force that acts on the particle.

Name: The figure shows a particle that carries a charge of q0 = -2.85 × 10^-6 C. It is moving along the +y axis at a speed of v = 4.99 × 10^6 m/s. A magnetic field B of magnitude 3.45 × 10^-5 T is directed along the +z axis, and an electric field E of magnitude 112 N/C points along the -x axis. Determine (a) the magnitude and (b) direction (as an angle within x-y plane with respect to +x-axis in the range (-180°, 180°]) of the net force that acts on the particle.
Uploaded: 2022-11-09T20:35:12-08:00
Duration: 2 min 15 s
Channel: Timothy James

          The figure shows a particle that carries a charge of q0 = -2.85 × 10^-6 C. It is moving along the +y axis at a speed of v = 4.99 × 10^6 m/s. A magnetic field B of magnitude 3.45 × 10^-5 T is directed along the +z axis, and an electric field E of magnitude 112 N/C points along the -x axis. Determine (a) the magnitude and (b) direction (as an angle within x-y plane with respect to +x-axis in the range (-180°, 180°]) of the net force that acts on the particle.

The figure shows a particle that carries a charge of q0 = -2.85 × 10^-6 C. It is moving along the +y axis at a speed of v = 4.99 × 10^6 m/s. A magnetic field B of magnitude 3.45 × 10^-5 T is directed along the +z axis, and an electric field E of magnitude 112 N/C points along the -x axis. Determine (a) the magnitude and (b) direction (as an angle within x-y plane with respect to +x-axis in the range (-180°, 180°]) of the net force that acts on the particle.

Added by Julia P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Timothy James

11/09/2022

Step 1

85 \times 10^{-6} \, C \) \( v = 4.99 \times 10^{6} \, m/s \) \( B = 3.45 \times 10^{-5} \, T \) Substitute the values: \( F = (-2.85 \times 10^{-6}) \times (4.99 \times 10^{6}) \times (3.45 \times 10^{-5}) \) Calculate the magnitude of the force. ** Show more…

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The figure shows a particle that carries a charge of q0 = -2.85 x 10^-6 C. It is moving along the +y axis at a speed of v = 4.99 x 10^6 m/s. A magnetic field B of magnitude 3.45 x 10^-5 T is directed along the +z axis, and an electric field E of magnitude 112 N/C points along the -x axis. Determine (a) the magnitude and (b) direction (as an angle within x-y plane with respect to +x-axis in the range (-180°, 180°]) of the net force that acts on the particle.