00:01
So for this question, we're told that we're given the graph of the velocity function, and we're told that the motion begins with an initial position of s of zero equals 1.
00:17
So at time equals zero, the position is at 1.
00:21
And part a asked for the displacement.
00:31
All right.
00:32
In other words, the displacement between time equals zero and time equals 10.
00:40
So in other words, where does the particle going to be at t equals 10? right.
00:47
So the idea here is that we need to calculate this area between the curve and the x -axis.
00:55
And remember, area below the x -axis is going to be negative.
00:58
So if i look at this area right here, right, this is simply a triangle with a height of two and a base of two.
01:06
So this area right here is going to be one -half base of two.
01:12
Height of two, which is simply two.
01:15
And that's a positive two.
01:17
If i look at this area, right, i see that this is a trapezoid.
01:23
So the area for a trapezoid is one half, one base.
01:30
So we'll call this base one here.
01:32
So from two to seven, that's a base of five, plus from three to six, that's a base of three times a height of two.
01:45
So 5 plus 3 is 4.
01:47
Sorry, 5 plus 3 is 8 and then times a half is 4 times 2 is 8.
01:52
And again, this area is below the curve, so it's going to be a negative 8.
01:56
Negative 8...