Question

The final number of molecules produced in 30 cycles of the PCR process is ? $2^{2}$ ? $2^{10}$ ? $2^{20}$ ? $2^{30}$

          The final number of molecules produced in 30 cycles of the PCR process is
? $2^{2}$
? $2^{10}$
? $2^{20}$
? $2^{30}$
        
The final number of molecules produced in 30 cycles of the PCR process is
? 2^2
? 2^10
? 2^20
? 2^30

Added by Regina V.

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Biology for AP Courses
Biology for AP Courses
Julianne Zedalis, John Eggebrecht
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The final number of molecules produced in 30 cycles of the PCR process is 2^(2) 2^(10) 2^(20) 2^(30) The final number of molecules produced in 30 cycles of the PCR process is 0210 230
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Transcript

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0:00 Okay.
00:02 So suppose a polymerous chain reaction or pcr amplification begins with exactly one double -stranded template dna.
00:11 How many dna molecules are present after 30 cycle of pcr, assuming there is no limitation in substrate and enzyme activity? so now let's take a look.
00:21 So you start out with one double -stranded dna.
00:25 So after first cycle of pcr, you end up have two.
00:37 After second, you have four.
00:47 So if we want to use our mass to deduce the mass rule, you can tell our formula, you can see in the beginning you have two to the zero power, which is one dna molecule.
01:02 So after the first round of replication or dna pcr reaction, you have two to the first power, which is two copies of number, strain of dna.
01:15 And then after the second round of cycle pcr, you have two to the second power, which is four copy of dna.
01:24 So according to this rule, when you have 30s cycle, so you have two to the 30s power.
01:35 So this is the total number of dna that is going to present at the end of 30 cycle.
01:42 So remember, the exponent is going to be the same as the number of cycles.
01:47 So if it's 29 cycle, it's going to be 2 to the 29th power.
01:52 So now to calculate 2 to the 30's power, all we have to do just do our math, 30 equals 1 ,773 ,741 ,000, and 8244 copies of double -stranded.
02:14 Dna.
02:15 So remember, the formula is 2 to the nth.
02:19 The n equals the number of cycles.
02:23 Question two.
02:25 Suppose dna polymerase introduce a single point mutation during cycle 11.
02:30 How many mutant dna molecule are present at the end of 30 cycles of pcr? so now, let's say this is cycle 11, and then you introduce a point mutation right here.
02:43 But this is not a double strand it's only a single strand.
02:47 So after the 12th cycle of pcr and you will have one double -stranded dna because both strand now will have the point mutation which i use red color and this is the 12 cycle and then at 13 cycle and this strand is gonna again replicate so you have two double -stranded dna that both have the single mutation...
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