The first K+ ion leaves the cell No ion permeability = no membrane potential K+ leak channel Equilibrium potential of -90 mV +1 Electrical gradient -1 Concentration gradient 5 mM K+ 150 mM K+
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The first K+ ion leaves the cell: This means that one K+ ion moves from inside the cell to outside the cell. Show more…
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Na+=20 mM Na+ =140 mM K+ = 5 mM Cl-=145 mM K+=unknown mM Cl- =5 mM A-(impermeable anion)= 165 mM Impermeable non-electrolytes = unknown mM Outside the Cell Inside the Cell
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Given the below information, estimate the membrane potential of the relevant neuron: A. Approximately +50 mV B. Approximately -60 mV C. Approximately -90 mV Ion Equilibrium Potential Relative Permeability Na +50 mV 10 K -60 mV 1 Cl -90 mV 0.5
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The membrane potential of a cell is determined by the relative permeability of the membrane to various ions. When acetylcholine binds to its receptors on the postsynaptic muscle membrane, it causes a massive opening of channels that are equally permeable to sodium and potassium ions. Under these conditions, $$V_{m}=\left(V_{K^{*}}+V_{N_{A}^{*}}\right) / 2$$ If $\left[\mathrm{K}^{+}_{\text {in }}\right]=140 \mathrm{mM}$ and $\left[\mathrm{Na}_{\text {in }}^{+}\right]=10 \mathrm{mM}$ for the muscle cell, and $\left[\mathrm{Na}_{\text {out }}^{+}\right]=150 \mathrm{mM}$ and $\left[\mathrm{K}_{\text {cut }}^{+}\right]=5 \mathrm{mM},$ what is the membrane potential of the neuromuscular junction of an acetylcholine-stimulated muscle?
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