00:01
So in this question, a certain experiment is carried out and 1 gram of sodium bicarbonate reacts with 1 gram of citric acid.
00:10
So this is the reaction that occurs, this is the reaction that occurs and we have to find which is the limiting gradient, what is the mass of the current acid produced, and also the mass of the excess reactant remaining after all the limiting reactant is completely consumed.
00:29
So we have the equation here, complete balanced equation.
00:36
Now first we'll find the moles of each reactant, that is, moles of sodium bicarbonate and moles of citric acid.
00:43
So, moles of sodium bicarbonate is equal to given mass by molar mass.
00:46
The molar mass of sodium bicarbonate is 84 .007, and the given mass is 1 gram, so we'll divide, and we'll get the number of moles of sodium bicarbonate as 0 .119.
00:56
Similarly, we will get the moles of citric acid, that is 1 gram by 1902 .124, that is the, this is the molar mass of citric acid.
01:06
So we'll get the number of moles of citric acid at 0 .0052.
01:10
Now see the equation, we can say that 1 mole of citric acid completely reacts with 3 moles of sodium bicarbonate.
01:19
So 0 .0052 moles of citric acid will completely react with 3 by 1 into 0 .005...