00:01
So let us start with the concept which we are going to use here for this question.
00:08
So mean can be given by x bar is equals to or overall mean summation of n i times of x i bar where i varying from 1 to n divided by summation of i varying from 1 to n n i.
00:27
According to question we are given that the sample size n1 equals to n2 is equals to n3 is equals to 6.
00:38
For the first one the mean is x1 bar which is equals to 156.
00:45
For the second is x2 bar which is 142.
00:48
And for the third it is x3 bar which is equals to 134.
00:54
In similar way, the standard deviation has been given as 1 of square, sorry variance is given.
01:03
S1 square 164 .4, s2 square 131 .2 and s3 of square 110 .4.
01:17
So, first of all, let us compute the overall mean, x bar.
01:22
So this should be equals to as we have written it should vary from 1 to 3 submission and i x i of bar that's all divided by the submission of i varying from 1 to 3 of ni so that should be equals to 6 into 156 plus 6 into 142 plus because 6 into 134 that whole divided by 18.
01:55
So this will come out equals to.
01:58
Okay x bar will be equals to 144...