The following data represent the high-temperature distribution for a summer month in a city for some of the last 130 years. Treat the data as a population. Complete parts (a) through (c). Temperature (°F) 50-59 60-69 70-79 80-89 90-99 100-109 Days 2 304 1486 1487 338 10 (a) Approximate the mean and standard deviation for temperature. ? = [ ] °F (Round to one decimal place as needed.)
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First, we need to find the midpoint of each temperature range. This can be done by adding the lower and upper bounds of each range and dividing by 2. Midpoints: 50-59: $\frac{50+59}{2} = 54.5$ 60-69: $\frac{60+69}{2} = 64.5$ 70-79: $\frac{70+79}{2} = 74.5$ 80-89: Show more…
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