2. The following diagram shows triangle ABC. diagram not to scale B 100° 6 10 A C AB = 6cm, BC = 10cm, and AB?C = 100°. (a) Find AC. (b) Find ?BCA.
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AC^2 = AB^2 + BC^2 - 2(AB)(BC)cos(ABC) AC^2 = 6^2 + 10^2 - 2(6)(10)cos(100°) AC^2 = 36 + 100 - 120cos(100°) Now, we can find the value of cos(100°) using a calculator: cos(100°) ≈ -0.1736 AC^2 = 36 + 100 + 120(0.1736) AC^2 ≈ 156.432 Now, we can find AC by Show more…
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