00:01
Hello, student.
00:02
So in this question, you are given that we have this equation, equilibrium equation, right? and this mass is given of each of the compound, right? and the volume is given, the reaction mixture volume is given as 2 .5 meters.
00:16
You have to find out the kc for this reaction.
00:18
So if we know the formula of kc, so the kc is equal to, kc is equal to the concentration of product.
00:27
We have the concentration of product divided by a raise to par we put here the coefficient okay stochometric coefficient in the reaction and then divided by the reactants divided by the reactants of the reaction and again here we have the coefficient so in this equation you can see what is the product product is our n o b r so the coefficient we have is two so raise to par two and the reactant we have two reactants so we have first one as no it has the coefficient two so it is multiplied by the concentration of vr2 fine so we are given with the mass but we have to find out the concentration so how we are going to find out the concentration so if we have to find out the concentration of no suppose so the formula we are going to use is mass of no mass of no divided by molar mass of no, molar mass of no, and then we have the volume of the reaction.
01:44
All right, so mass is given to us, it is 1 .25 grams.
01:50
The molar mass we know, it is 30 grams per moon.
01:56
All right, and then volume we have is 2 .5 liters.
02:00
So this will comes out to be 0 .061 .7 molar.
02:07
Sorry, not 61, it is 16.
02:09
0 .0167 molar.
02:12
All right.
02:14
So this is the concentration of no.
02:18
So next we have, we have to find out the concentration of br2...