00:01
Hello students, let us solve this question.
00:03
In this question we have to determine the structure from the given proton nmr spectra and the molecule is having the formula c7h14o2.
00:15
It is an ester which means there will be 6 carbon and 1 carbon from the ester group.
00:24
So we are given the protons like 6 hydrogen doublet, 1 hydrogen nonet, 2 hydrogen doublet, 2 hydrogen quartet, 2 hydrogen, 3 hydrogen triplet.
00:57
So there is a 6 hydrogen doublet, 6 hydrogen means it will be from a ch3 group like 2 ch3 group attached to a ch group, then only it will come like a doublet.
01:16
So the structure will be like this ch, ch3 and ch3.
01:23
Then there is a 1 hydrogen nonet.
01:26
So this is 6 and for this particular proton, if these protons are coupling, then it will be 6 plus 1, 7 but we have a nonet which means this ch is attached to a ch2 group.
01:46
Then this proton will experience 2 plus 3 plus 3 and n is equal to 6 plus 2 8, then n plus 1 signal will be coming, so 9.
02:01
So this is the structure and now we have 1, 2, 3, 4 carbon, then we have to go for that ester group...