The following is NOT a necessary step in homologous recombination: Double strand break Strand invasion D-loop formation Antibiotic resistance Why do you think E. coli mutants that lack the recA gene experience chromosomal loss and cell death? Because they have double-strand breaks that are not sufficiently repaired. Because they cannot grow in the presence of sucrose. Because they cannot carry out homologous recombination during horizontal gene transfer. Because they cannot replicate DNA. What is the normal purpose of CRISPR systems in bacteria and archaea? To insert double strand breaks into specific bacterial or archaeal genomic loci. To recognize and destroy viral DNA. To carry out precise genome editing. To regulate gene expression.
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The following is NOT a necessary step in homologous recombination: \[\boxed{\text{Antibiotic resistance}}\] Show more…
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Consider the two processes involved in repairing double-strand DNA breaks. Which process, homologous recombination or NHEJ, is more likely to restore the original gene sequence and why? Match the words in the left column to the appropriate blanks in the sentences on the right. Homologous recombination requires exact sequence homology between recombining partners and can occur only in the presence of a homologous undamaged chromosome. NHEJ joins any two damaged chromosome ends, with no testing for sequence homology between the rejoining partners. Therefore, only homologous recombination has a finite chance of restoring the original gene sequence.
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A piece of DNA is brought into a host cell. However, its sequence does not align or match with the sequence on the genome. The bacteria then undergo replication. What is likely to happen to this new piece of DNA? a) The piece of DNA will undergo homologous recombination and be maintained and found in the genome of the bacterium's offspring. b) The piece of DNA will undergo homologous recombination but will not be maintained and found in the genome of the bacterium's offspring. c) The piece of DNA will not undergo homologous recombination but will be maintained and found in the genome of the bacterium's offspring. d) The piece of DNA will not undergo homologous recombination and will not be maintained and found in the genome of the bacterium's offspring.
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