The following sample contains 16 measurements was selected from a population that is approximately normally distributed. 92 80 98 102 96 105 79 120 106 100 97 83 100 83 104 117 Construct an 90% confidence interval for the population mean.
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x̄ = (92 + 80 + 98 + 102 + 96 + 105 + 79 + 120 + 106 + 100 + 97 + 83 + 100 + 83 + 104 + 117) / 16 x̄ = 1596 / 16 x̄ = 99.75 Now, let's calculate the sample standard deviation (s): s = √[(Σ(x - x̄)²) / (n - 1)] s = √[(92-99.75)² + (80-99.75)² + ... + Show more…
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