The following tests were obtained over a 24-hour period. Urine volume 1.2 L Urine [inulin] 110 mg% Urine [creatinine] 170 mg% Plasma [inulin] 0.8 mg% Plasma [creatinine] 1.2 mg% Hematocrit 0.4 a) Calculate the clearance of inulin. b) Calculate the clearance of creatinine. c) What is the GFR? d) If the filtration fraction is 0.18, estimate the ERPF. Remember that the ERPF is usually 90% of the RPF.
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The formula for clearance (C) is given by: \[ C = \frac{(U \times V)}{P} \] where \( U \) is the urine concentration of the substance, \( V \) is the urine flow rate, and \( P \) is the plasma concentration of the substance. Show more…
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The following test results were obtained over a 24-hour period: urine volume = 1.4 L; urine [inulin] = 100 mg%; urine [urea] = 220 mmol/L; urine [PAH] = 70 mg/mL; plasma [inulin] = 1 mg%; plasma [urea] = 5 mmol/L; plasma [PAH] = 0.2 mg/mL; hematocrit = 0.4. Calculate the following. a. Clearance of inulin, clearance of urea, and clearance of PAH b. ERPF c. Rate of urea filtration d. Rate of urea excretion e. Rate of urea reabsorption f. Rate of PAH filtration g. Rate of PAH excretion h. Rate of PAH secretion
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