The formula for measuring sound intensity in decibels $D$ is defined by the equation $D=10 \log \left(\frac{1}{I_{0}}\right),$ where $I$ is the intensity of the sound in watts per square meter and $I_{0}=10^{-12}$ is the lowest level of sound that the average person can hear. How many decibels are emitted from a rock concert with a sound intensity of 4.7$\cdot 10^{-1}$ watts per square meter?
Added by Phillip P.
Step 1
First, we need to plug in the given values into the formula: $D=10 \log \left(\frac{1}{I_{0}}ight)=10 \log \left(\frac{1}{10^{-12}}ight)=10 \log (10^{12}ight)$ Show more…
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The formula for measuring sound intensity in decibels $D$ is defined by the equation $D=10 \log \left(\frac{1}{I_{0}}\right),$ where $I$ is the intensity of the sound in watts per square meter and $I_{0}=10^{-12}$ is the lowest level of sound that the average person can hear. How many decibels are emitted from a large orchestra with a sound intensity of 6.3$\cdot 10^{-3}$ watts per square meter?
Sam S.
The formula for measuring sound intensity in decibels D is defined by the equation D = 10log(I/I0), where I is the intensity of the sound in watts per square meter and I0 = 10^(-12) is the lowest level of sound that the average person can hear. How many decibels are emitted from a rock concert with a sound intensity of 4.7 x 10^(-1) watts per square meter?
Supreeta N.
The loudness level of a sound, $D,$ in decibels, is given by the formula $$ D=10 \log \left(10^{12} I\right) $$ where $I$ is the intensity of the sound, in watts per meter.$^{2} .$ Decibel levels range from $0,$ a barely audible sound, to $160,$ a sound resulting in a ruptured eardrum. (Any exposure to sounds of I30 decibels or higher puts a person at immediate risk for hearing damage.) Use the formula to solve What is the decibel level of a normal conversation, $3.2 \times 10^{-6}$ watt per meter $^{2} ?$
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