00:01
Hello students, in this question given as a acceleration at the mars planet is given as 3 .7 meter per second square.
00:12
Now in the first part of the question we have to calculate the length of the pendulum for the time period 1 second on the earth.
00:22
So at this we know that t is equals to 2 pi under root l upon g.
00:29
And for the earth we will take the acceleration at g at this.
00:33
So l will be equal to the, that will be equal to the te square g upon 4 pi square.
00:42
Now this will be equal to the t is equals to 1 second square into g is equals to 9 .81 meter per second square into 4 upon 4 pi square.
00:55
So after calculation the length at the earth will be equal to the 0 .25 meter.
01:07
And next we have to calculate the length of the pendulum at the mars and the time period of the mars is given as again 1 second.
01:16
So for this we will again write, we can write this is equals to the time period square time.
01:23
So time square 1 second square into the acceleration.
01:27
Acceleration on the mars is given as 3 .7 meter per second square upon 4 pi square.
01:36
So after calculation we will get the length of the pendulum at the mars will be equal to the 0 .094 meter.
01:45
In the next part of the question given as the spring constant is equals to 10 newton, 10 newton per second, 10 newton per second is given as here...