00:01
Hey everyone, welcome back.
00:01
In this question we are given that exhalation due to gravity on the planet mars is given as 3 .7 meter per second square and exhalation due to gravity on the surface of earth is 9 .8 meter per second square.
00:16
These values are given in the question.
00:19
And in the first part of question we are told that we have to find out the length of pendulum if the time period, if time period is 2 .8 seconds on the first part of the question, the surface of earth.
00:31
On earth, i can see.
00:33
Now as we know that time period is given by 2 pi root over l by g.
00:37
So from this formula, i can write the value of length as t squared divided by 4 pi square into exhalation due to gravity on earth.
00:45
So time period is 2 .8 seconds.
00:48
This will be 2 .8 square divided by 4 pi square into exhalation due to gravity on surface of earth, that is 9 .8.
00:54
So from here the length is coming out as 1 .95 meter.
00:58
Now in the second part of this particular question we are asked to find out again the length of simple pendulum if time period is 2 .8 seconds but this time on mars.
01:09
Okay, so nothing will change but this value of g will change because this particular pendulum is on mars now.
01:18
So length will be t squared divided by 4 pi square into exhalation due to gravity on surface of mars.
01:24
So that will be 2 .8 square divided by 4 pi square...