The function $Y(t) = 3\sin(Bt)$ with $B > 0$, has a period of $\frac{2\pi}{B}$. True False
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In this case, the coefficient of t is B, so the period is 2π/B. Given that the period is 2π/3, we can set up the equation 2π/B = 2π/3 and solve for B. 2π/B = 2π/3 Cross multiplying, we get: 3(2π) = B(2π) 6π = 2πB Dividing both sides by 2π, we get: Show more…
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