Question

The gas phase decomposition of dinitrogen pentoxide at 335 K N2O5(g)-->2NO2(g)+½O2(g) is first order in N2O5 with a rate constant of 4.70x10^-3s^-1. How much time is required for 81.9% of the N2O5 intially present in a reaction flask to be converted to product at this temperature? s

Name: the gas phase decomposition of dinitrogen pentoxide at 335 k n2o5g 2no2g12o2g is first order in n2o5 with a rate constant of 470x10 3s 1 how much time is required for 819 of the n2o5 intiall 69305
Uploaded: 2022-04-05T14:01:03-08:00
Duration: 2 min 11 s
Channel: Shyam P
Description: the gas phase decomposition of dinitrogen pentoxide at 335 k n2o5g 2no2g12o2g is first order in n2o5 with a rate constant of 470x10 3s 1 how much time is required for 819 of the n2o5 intiall 69305

          The gas phase decomposition of dinitrogen pentoxide at 335 K
N2O5(g)-->2NO2(g)+½O2(g)
is first order in N2O5 with a rate constant of 4.70x10^-3s^-1.
How much time is required for 81.9% of the N2O5 intially present in a reaction flask to be converted to product at this temperature?
s

Added by Remedios J.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Shyam P

04/05/2022

Step 1

Since we are looking for the time required for 81.9% of N2O5 to decompose, we can denote the initial concentration as [N2O5]₀. Show more…

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The gas phase decomposition of dinitrogen pentoxide at 335 K N2O5(g)-->2NO2(g)+½O2(g) is first order in N2O5 with a rate constant of 4.70x10^-3s^-1. How much time is required for 81.9% of the N2O5 intially present in a reaction flask to be converted to product at this temperature? s