00:01
Hello everyone, let's solve the given question.
00:02
So, as according to the question we are having y4 -y is equals to 0, y0 is equals to 0, y ' of 0 is equals to 1, y' ' of 0 is equals to 2, y'' ' of 0 is equals to 3.
00:18
Now, taking laplace transform then we get l y4 -l y is equals to 0, then l y4 is equals to s4 l y of t minus x cube y of 0 minus s square y ' of 0 minus s y' ' of 0 minus s y'' ' of 0.
00:49
Then we get l y is equals to l y of t.
00:55
So, as according to this we get the equation as s 4 -1 l y of t minus 5 cube y 0 minus s square y ' of 0 minus s y' ' of 0 minus y'' ' of 0 is equals to 0.
01:17
Then we get s 4 -1 l of y t minus x cube multiplied by 0 minus s square multiplied by 1 minus s multiplied by 2 minus 3 is equals to 0.
01:34
On further simplifying this we get it as s 4 -1 l y of t minus s square minus 2 s minus 3 is equals to 0.
01:50
Then we get l y of t is equals to s square plus 2 s plus 3 divided by s 4 -1...