00:01
So this question is given that there is a great pyramid of geiza in egypt.
00:05
Okay, so there is also given that this is in the form of a right square pyramid.
00:12
Okay, so the base is a square with each side 2 .30 meters.
00:18
Also the angle a, b, b is given us 15 .3.
00:22
M is the midpoint of the abe and o is the center of the base.
00:26
V is the vertex.
00:28
So we have to find three things, that is the final length of the vm.
00:31
That is this one, vn, stand height.
00:35
Find the height of the pyramid, vo, and the volume of the pyramid.
00:38
So first find the length of the vm.
00:41
Now first consider this triangle.
00:43
That is, i will mark here, let's consider vmb, that is vmb.
00:50
This triangle, vmb.
00:54
Consider this triangle, okay, this angle is given us a 50 .8 .2 degree.
00:58
Now we have to calculate vm, okay.
01:00
We know bm, because, a b is given to 30 meters so bm will be half because m is a midpoint as m is a midpoint bm will be half of ab that is 150 meter 20 by 2 okay so we know this point and we have to convert this and we know this angle so we can apply tan so t t t t50 .3 will be opposite side by base that is this this is 90 degree so this is 90 degree so we can set t tn 50 .3 equal to vm by bn that is equal to vm is equal to bm into t s t s t t t t t t t t t t t t t t t t t t t t t t t t t t t t t.
01:32
So we can say 10 958 .3 degree that is equal to 115 into bm equals 150 to 115 into 1 .619 that is 186 .20.
01:40
So you find the value of vm.
01:41
Now we have to find the value of height that is vo.
01:44
Now we have to see another triangle that is this triangle...