00:01
In part a, here we need to assume the correct reaction.
00:04
So we have c6h12 .06 plus we have nh3 yields to, so this would be b or beta nh3, so yields to 0 .59 ch nno, biomass plus 0 .59, biomass plus 0 .5.
00:35
43 c3h803 plus 1 .54 carbon dioxide plus 1 .3c2h5oh plus 0 .036h2o.
00:55
Here, taking the molecular weight of elements, your carbon is 12, your nitrogen is 14, your oxygen is 16 and your hydrogen is 1 the biomass yield is usually calculated as grams of biomass divided by gram of sugar then here one mole of sugar gives 0 .59 moles of your biomass and one mole of sugar that is equal to 6 times 12 plus 12 times 1 plus 6 times 16 is equals to 180 grams.
01:44
Then the molecular weight of the biomass, so we have the molecular weight of the biomass, which is equals to 0 .59 ch, and this is 1 .74, 0 .2, oxygen is 0 .455 .5.
02:13
Is equals to 0 .59 times 12 plus 1 .74 times 1 plus 0 .2 times 14 plus 0 .45 times 16.
02:36
Now the molecular weight of your biomass will be equal to 0 .5912 plus 1 .7.
02:46
Plus 2 .8 plus 7 .2...