Question

The half-life of $^{222}Rn$ is 3.8 days. A sample of $^{222}Rn$ is allowed to decay for 15.2 days and after this time, 5.6 mmol remained. What was the initial quantity of $^{222}Rn$? a. 0.09 mol b. 0.045 mol c. 45 mmol d. 0.9 mol

          The half-life of $^{222}Rn$ is 3.8 days. A sample of $^{222}Rn$ is allowed to decay for 15.2 days and after this time, 5.6 mmol remained. What was the initial quantity of $^{222}Rn$? 
a. 0.09 mol
b. 0.045 mol
c. 45 mmol
d. 0.9 mol

The half-life of ^222Rn is 3.8 days. A sample of ^222Rn is allowed to decay for 15.2 days and after this time, 5.6 mmol remained. What was the initial quantity of ^222Rn?
a. 0.09 mol
b. 0.045 mol
c. 45 mmol
d. 0.9 mol

Added by Philip R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Timothy James

11/16/2022

Step 1

The number of half-lives (n) can be calculated using the formula: n = (time passed) / (half-life) n = 15.2 days / 3.8 days n = 4 Show more…

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The half-life of ^(222)Rn is 3.8 days. A sample of ^(222)Rn is allowed to decay for 15.2 days and after this time, 5.6 mmol remained. What was the initial quantity of 222Rn ? a. 0.09mol b. 0.045mol C. 45mmol d. 0.9mol 5 points Save The half-life of 222Rn is 3.8 days. A sample of 222Rn is allowed to decay for 15.2 days and after this time, 5.6 mmol remained. What was the initial quantity of 222Rn? Oa.0.09 mol Ob.0.045mol Oc.45 mmol O d.o.9 mol