The half-life of krypton-91 (91Kr) is 10 s. At time t = 0, a heavy canister contains 3 g of this radioactive gas. After how long will the amount of 91Kr remaining be reduced to 1 µg (1 microgram, or 10^(-6) g)? (Round your answer to the nearest whole number.)
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In this case, the half-life of krypton-91 is 10 seconds, which means every 10 seconds, half of the remaining krypton-91 decays. Show more…
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