The human body obtains 955 kJ of energy from a candy bar.? If this energy were used to vaporize water at 100.0 āC, how much water (in liters) could be vaporized? (Assume the density of water is 1.00 g/mL.)
Added by Gregory D.
Step 1
First, we need to convert the energy obtained from the candy bar from kJ to J, since the unit of energy required for vaporizing water is Joules. 955 kJ = 955,000 J Show moreā¦
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The human body obtains 915 $\mathrm{kJ}$ of energy from a candy bar. If this energy were used to vaporize water at $100.0^{\circ} \mathrm{C}$ , how much water (in liters) could be vaporized? (Assume the density of water is 1.00 $\mathrm{g} / \mathrm{mL.}$ .
The human body obtains 915 kJ of energy from a candy bar. If this energy were used to vaporize water at 100 C, how much water (in liters) could be vaporized? (Assume the density of water is 1.00 g>mL.)
The human body obtains 1078 kJ from a candy bar. If this energy were used to vaporize water at $100^{\circ} \mathrm{C}$, how much water in liters could be vaporized? (Assume that the density of water is $1.0 \mathrm{g} / \mathrm{mL} .)$
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