Question
The human body obtains 1078 kJ from a candy bar. If this energy were used to vaporize water at $100^{\circ} \mathrm{C}$, how much water in liters could be vaporized? (Assume that the density of water is $1.0 \mathrm{g} / \mathrm{mL} .)$
Step 1
7 kJ. The energy obtained from the candy bar is 1078 kJ. We can calculate the number of moles of water that can be vaporized by this energy using the formula: \[ \text{Number of moles} = \frac{\text{Energy obtained}}{\text{Heat of vaporization}} \] Substituting Show more…
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The human body obtains 915 $\mathrm{kJ}$ of energy from a candy bar. If this energy were used to vaporize water at $100.0^{\circ} \mathrm{C}$ , how much water (in liters) could be vaporized? (Assume the density of water is 1.00 $\mathrm{g} / \mathrm{mL.}$ .
The human body obtains 915 kJ of energy from a candy bar. If this energy were used to vaporize water at 100 C, how much water (in liters) could be vaporized? (Assume the density of water is 1.00 g>mL.)
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