The hydrogen electron jumping from E5 to E2 emits light with the wavelength of 434nm. Calculate the energy of the E5 orbital. Given E2 = -5.45x10^-19 J.
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Step 1
The energy difference between two energy levels can be calculated using the formula: ΔE = hc / λ Where: ΔE = Energy difference between two energy levels h = Planck's constant (6.626 x 10^-34 J*s) c = speed of light (3.00 x 10^8 m/s) λ = wavelength of emitted Show more…
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Based on the equation ΔE = -2.0×10^-18 J (1/n2 - 1/n1^2), the wavelength of the light that must be absorbed to excite a hydrogen electron from level n = 1 to level n = 2 will be (h = 6.625×10^-34 Js, C = 3×10^8 ms^-1).
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