Question

The indefinite integral $\int \frac{2}{x^2 - 1} dx$ is equal to. A. $ln((x+1)(x-1)) + C$ B. $ln(\frac{x-1}{x+1}) + C$ C. $ln((x+1)^2(x-1)^2) + C$ D. $ln(\frac{(x+1)^2}{x-1}) + C$

          The indefinite integral $\int \frac{2}{x^2 - 1} dx$ is equal to.
A. $ln((x+1)(x-1)) + C$
B. $ln(\frac{x-1}{x+1}) + C$
C. $ln((x+1)^2(x-1)^2) + C$
D. $ln(\frac{(x+1)^2}{x-1}) + C$

The indefinite integral ∫(2)/(x^2 - 1) dx is equal to.
A. ln((x+1)(x-1)) + C
B. ln((x-1)/(x+1)) + C
C. ln((x+1)^2(x-1)^2) + C
D. ln(((x+1)^2)/(x-1)) + C

Added by Purificaci-N G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Tyler Moulton

10/12/2021

Step 1

We can rewrite the integrand as (2)/((x+1)(x-1)). Show more…

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The indefinite integral int (2)/(x^(2)-1)dx is equal to. A. ln((x+1)(x-1))+C B. ln((x-1)/(x+1))+C C. ln((x+1)^(2)(x-1)^(2))+C D. ln((x+1)/(x-1))^(2)+C 2 The indefinite integral dx is equal to. A.ln(x+1)x-1)+C B. ln +C x+1 C.1n(x+1x-1)+C x+1 D. ln x-1 +C