The inductor shown in Fig. 30.18 has inductance 0.260 $\mathrm{H}$ and carries a current in the direction shown. The current is changing at a constant rate. (a) The potential between points $a$ and $b$ is $V_{a b}=1.04 \mathrm{V},$ with point $a$ at higher potential. Is the current increasing or decreasing? b) If the current at $t=0$ is 12.0 $\mathrm{A}$ , what is the current at $t=2.00 \mathrm{s} ?$
Added by Christopher H.
Step 1
04$ V, $L = 0.26$ H $1.04 = -0.26 \frac{dI}{dt}$ Solving for $\frac{dI}{dt}$, we get $\frac{dI}{dt} = -4$ A/s Since the potential difference is positive, the negative sign indicates that the current is decreasing. ** Show more…
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