Question

The initial-rate data in the table below were obtained for the reaction represented below. What is the experimental rate law for this reaction. A + B ? 2 C Exp No. | Initial [A] (mol L?¹) | Initial [B] (mol L?¹) | Initial rate of formation of [C] (mol L?¹ Sec?¹) 1 | 0.1 | 0.1 | 0.00025 2 | 0.2 | 0.1 | 0.0005 3 | 0.2 | 0.5 | 0.0125 Select one: rate = k [A]/[B] rate = k[A][B]³ rate = k[A][B]² rate = k[A]²[B]² rate = k[A][B]

          The initial-rate data in the table below were obtained for the reaction represented below. What is the experimental rate law for this reaction.
A + B ? 2 C

Exp No. | Initial [A] (mol L?¹) | Initial [B] (mol L?¹) | Initial rate of formation of [C] (mol L?¹ Sec?¹)
1 | 0.1 | 0.1 | 0.00025
2 | 0.2 | 0.1 | 0.0005
3 | 0.2 | 0.5 | 0.0125

Select one:
rate = k [A]/[B]
rate = k[A][B]³
rate = k[A][B]²
rate = k[A]²[B]²
rate = k[A][B]

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The initial-rate data in the table below were obtained for the reaction represented below. What is the experimental rate law for this reaction.
A + B ? 2 C

Exp No. | Initial [A] (mol L?¹) | Initial [B] (mol L?¹) | Initial rate of formation of [C] (mol L?¹ Sec?¹)
1 | 0.1 | 0.1 | 0.00025
2 | 0.2 | 0.1 | 0.0005
3 | 0.2 | 0.5 | 0.0125

Select one:
rate = k [A]/[B]
rate = k[A][B]³
rate = k[A][B]²
rate = k[A]²[B]²
rate = k[A][B]

Added by Peggy H.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Nicole Smina

12/23/2022

Step 1

In this case, the initial rates are: rate kIAJIB] = 0.0005 rate kAIZIB] = 0.00025 Show more…

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The initial-rate data in the table below were obtained for the reaction represented below. What is the experimental rate law for this reaction: A + B ⅄ 2C? Exp No. Initial [A] (mol Lⁱ¹) Initial [B] (mol Lⁱ¹) Initial rate of formation of [C] (mol Lⁱ¹ Secⁱ¹) 1 0.1 0.1 0.00025 2 0.2 0.1 0.0005 3 0.2 0.5 0.0125 Select one: rate = k [A]/[B] rate = k[A][B]³ rate = k[A][B]² rate = k[A]²[B]² rate = k[A][B]

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