The Keq for the equilibrium below is 7.52 × 10^-2 at 480.0°C. 2Cl2 (g) + 2H2O (g) → 4HCl (g) + O2 (g) What is the value of Keq at this temperature for the following reaction? 2HCl (g) + 1/2 O2 (g) → Cl2 (g) + H2O (g)
Added by Felipe S.
Step 1
So, for the reversed reaction, the Keq is: Keq_reversed = 1 / (7.52 × 10^-2) = 13.30 Now, we need to divide the reversed reaction by 2 to match the given reaction: Show more…
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The Keq for the equilibrium below is 7.52 · 10^-2 at 480.0 °C. 2Cl2 (g) + 2H2O (g) ⇌ 4HCl (g) + O2 (g) What is the value of Keq at this temperature for the following reaction? HCl (g) + 1/2O2 (g) ⇌ 1/2Cl2 (g) + 1/2H2O (g) 0 1.91 1.88 x 10^-2 0.524 7.52 · 10^-2
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