2) (5 pts) The Keq for the equilibrium below is 7.52 !! 10-2 at 480.0!!C. 2 Cl2 (g) + 2 H2O (g) !! 4 HCl (g) + O2 (g) What is the value of Keq at this temperature for the following reaction? 6 HCl (g) + 3/2 O2 (g) !! 3 Cl2 (g) + 3 H2O (g)
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We can do this by reversing the given equation and multiplying it by 3/4: Given equation: 2 Cl2 + 2 H2O ⇌ 4 HCl + O2 Reversed equation: 4 HCl + O2 ⇌ 2 Cl2 + 2 H2O Multiplied by 3/4: 3 HCl + 3/2 O2 ⇌ 3/2 Cl2 + 3/2 H2O Now, we need to find the new Keq for the Show more…
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The Keq for the equilibrium below is 7.52 × 10^-2 at 480.0°C. 2Cl2 (g) + 2H2O (g) → 4HCl (g) + O2 (g) What is the value of Keq at this temperature for the following reaction? 2HCl (g) + 1/2 O2 (g) → Cl2 (g) + H2O (g)
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