the length of a rectangular poster is 10 more inches than three times its width. The area of the poster is 88 square inches. Solve for the dimensions (length and width ) of the poster.
Added by Jimmy E.
Step 1
Let \( w \) represent the width of the poster in inches. According to the problem, the length \( l \) of the poster is 10 more inches than three times its width. Therefore, we can express the length as \( l = 3w + 10 \). Show more…
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