The light intensity incident on a metallic surface produces photoelectrons with a maximum kinetic energy of 2 eV. The light intensity is doubled. Determine the maximum kinetic energy of the photoelectrons (in eV). A. 4 B. 2 C. √2 D. 3 E. 16
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Step 1: The maximum kinetic energy of photoelectrons is given by the equation \( K_{\text{max}} = eV - \phi \), where \( eV \) is the energy of the incident light and \( \phi \) is the work function. Show more…
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