Radiations of frequency, v, are incident on a photosensitive...

Radiations of frequency, $v$, are incident on a photosensitive metal. The maximum kinetic energy of photoelectrons is $E$. When the frequency of the incident radiations is doubled, what is the maximum kinetic energy of the photoelectrons?
(a) $2 E$
(b) $E / 2$
(c) $E+h v$
(d) $E-h v$

Key Concepts

Photoelectric Effect

The photoelectric effect is the process by which electrons are ejected from a material, typically a metal, when it is exposed to light of sufficiently high frequency. This phenomenon provided early evidence for the quantization of energy and the particle nature of light, serving as one of the foundational experiments that led to the development of quantum mechanics.

Photon Energy

Photon energy is determined by the frequency of the light, following the relationship E = h?, where h is Planck's constant and ? is the frequency. This concept is crucial in understanding how light interacts with matter, as higher frequency light carries more energy per photon, which can affect the emission characteristics of electrons from a material.

Work Function

The work function is the minimum energy required to remove an electron from the surface of a material. It is a characteristic property of the material in question and sets the energy threshold for the photoelectric effect; only photons with energy exceeding the work function will be able to eject electrons.

Einstein's Photoelectric Equation

Einstein's photoelectric equation, given by Kmax = h? - ?, where Kmax is the maximum kinetic energy of the emitted electrons and ? is the work function, encapsulates the energy balance during the photoelectric effect. This equation shows that the kinetic energy of the photoelectrons depends linearly on the frequency of the incident light, reinforcing the idea of quantized light energy.

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