The limit $\lim_{x \to +\infty} \frac{1 - \sin(5x)}{1 - \sqrt{1 - \frac{3}{x}}}$ (A) equals -5/3 (B) equals $-\infty$ (C) equals 0 (D) equals -1/3 (E) does not exist
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We have $$ L = \lim_{x \to +\infty} \frac{1 - \sin(5x)}{1 - \sqrt{1 - \frac{3}{x}}} $$ Since $-1 \le \sin(5x) \le 1$, the numerator $1 - \sin(5x)$ is bounded between 0 and 2. Show more…
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