The linear momentum of a skater of mass 50 Kg, at a position vector (3 î + 6 ĵ) m is of a skater (-1 î + 2 ĵ) kg m/s
Added by Pilar S.
Step 1
- Mass of the skater (m) = 50 kg - Position vector (r) = (3 î + 6 ĵ) m - Linear momentum (p) = (-1 î + 2 ĵ) kg m/s Show more…
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